{"status": "success", "data": {"description_md": "In the diagram, if $\\triangle ABC$ and $\\triangle PQR$ are equilateral, then $\\angle CXY$ equals\n\n<center><img class=\"problem-image\" src=\"/static/cayley/2007/crops/07_cayley_p15_fig.png\" alt=\"figure\" width=\"333\"></center>\n\n$\\text{(A)}\\ 30\u00b0\\qquad\\text{(B)}\\ 35\u00b0\\qquad\\text{(C)}\\ 40\u00b0\\qquad\\text{(D)}\\ 45\u00b0\\qquad\\text{(E)}\\ 50\u00b0$\n\n___\n\n**[Cayley](https://www.cemc.uwaterloo.ca/contests/past_contests.html#pcf), by [CEMC](https://cemc.uwaterloo.ca/), is licensed under the [CC BY-NC 3.0 DEED](https://creativecommons.org/licenses/by-nc/3.0/). They are not affiliated with or endorse TopsOJ in any way.**\n", "description_html": "<p>In the diagram, if <span class=\"katex--inline\">\\triangle ABC</span> and <span class=\"katex--inline\">\\triangle PQR</span> are equilateral, then <span class=\"katex--inline\">\\angle CXY</span> equals</p>\n<center><img class=\"problem-image\" src=\"/static/cayley/2007/crops/07_cayley_p15_fig.png\" alt=\"figure\" width=\"333\"></center>\n<p><span class=\"katex--inline\">\\text{(A)}\\ 30\u00b0\\qquad\\text{(B)}\\ 35\u00b0\\qquad\\text{(C)}\\ 40\u00b0\\qquad\\text{(D)}\\ 45\u00b0\\qquad\\text{(E)}\\ 50\u00b0</span></p>\n<hr>\n<p><strong><a href=\"https://www.cemc.uwaterloo.ca/contests/past_contests.html#pcf\">Cayley</a>, by <a href=\"https://cemc.uwaterloo.ca/\">CEMC</a>, is licensed under the <a href=\"https://creativecommons.org/licenses/by-nc/3.0/\">CC BY-NC 3.0 DEED</a>. They are not affiliated with or endorse TopsOJ in any way.</strong></p>\n", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 1, "problem_name": "2007 Cayley Problem 15", "can_next": true, "can_prev": true, "nxt": "/problem/07_cayley_p16", "prev": "/problem/07_cayley_p14"}}