{"status": "success", "data": {"description_md": "For positive numbers $x$ and $y$ the operation $x\\spadesuit y$ is defined as \n$$x\\spadesuit y = x -\\dfrac{1}{y}$$\nWhat is $2\\spadesuit (2\\spadesuit 2)$?\n\n$\\mathrm{(A)}\\ \\dfrac{2}{3}\n\\qquad\n\\mathrm{(B)}\\ 1\n\\qquad\n\\mathrm{(C)}\\ \\dfrac{4}{3}\n\\qquad\n\\mathrm{(D)}\\ \\dfrac{5}{3}\n\\qquad\n\\mathrm{(E)}\\ 2$", "description_html": "<p>For positive numbers  <span class=\"katex--inline\">x</span>  and  <span class=\"katex--inline\">y</span>  the operation  <span class=\"katex--inline\">x\\spadesuit y</span>  is defined as<br/>\n <span class=\"katex--display\">x\\spadesuit y = x -\\dfrac{1}{y}</span> <br/>\nWhat is  <span class=\"katex--inline\">2\\spadesuit (2\\spadesuit 2)</span> ?</p>\n<p> <span class=\"katex--inline\">\\mathrm{(A)}\\ \\dfrac{2}{3}\n\\qquad\n\\mathrm{(B)}\\ 1\n\\qquad\n\\mathrm{(C)}\\ \\dfrac{4}{3}\n\\qquad\n\\mathrm{(D)}\\ \\dfrac{5}{3}\n\\qquad\n\\mathrm{(E)}\\ 2</span> </p>\n<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 1, "problem_name": "2010 AMC 10A Problem 6", "can_next": true, "can_prev": true, "nxt": "/problem/10_amc10A_p07", "prev": "/problem/10_amc10A_p05"}}