{"status": "success", "data": {"description_md": "Angelina drove at an average rate of $80$ km/h and then stopped $20$ minutes for gas. After the stop, she drove at an average rate of $100$ km/h. Altogether she drove $250$ km in a total trip time of $3$ hours including the stop. Which equation could be used to solve for the time $t$ in hours that she drove before her stop?\n\n$\\mathrm{(A)}\\ 80t + 100\\left(\\frac{8}{3} -t\\right) = 250\n\\qquad\n\\mathrm{(B)}\\ 80t = 250 \n\\qquad\n\\mathrm{(C)}\\ 100t = 250$<br/>$\\mathrm{(D)}\\ 90t = 250\n\\qquad\n\\mathrm{(E)}\\ 80\\left(\\frac{8}{3} -t\\right) + 100t = 250$", "description_html": "<p>Angelina drove at an average rate of  <span class=\"katex--inline\">80</span>  km/h and then stopped  <span class=\"katex--inline\">20</span>  minutes for gas. After the stop, she drove at an average rate of  <span class=\"katex--inline\">100</span>  km/h. Altogether she drove  <span class=\"katex--inline\">250</span>  km in a total trip time of  <span class=\"katex--inline\">3</span>  hours including the stop. Which equation could be used to solve for the time  <span class=\"katex--inline\">t</span>  in hours that she drove before her stop?</p>\n<p> <span class=\"katex--inline\">\\mathrm{(A)}\\ 80t + 100\\left(\\frac{8}{3} -t\\right) = 250\n\\qquad\n\\mathrm{(B)}\\ 80t = 250 \n\\qquad\n\\mathrm{(C)}\\ 100t = 250</span> <br/> <span class=\"katex--inline\">\\mathrm{(D)}\\ 90t = 250\n\\qquad\n\\mathrm{(E)}\\ 80\\left(\\frac{8}{3} -t\\right) + 100t = 250</span> </p>\n<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 3, "problem_name": "2010 AMC 10A Problem 13", "can_next": true, "can_prev": true, "nxt": "/problem/10_amc10A_p14", "prev": "/problem/10_amc10A_p12"}}