{"status": "success", "data": {"description_md": "The number obtained from the last two nonzero digits of $90!$ is equal to $n$. What is $n$?\n\n$\\textbf{(A)}\\ 12 \\qquad \\textbf{(B)}\\ 32 \\qquad \\textbf{(C)}\\ 48 \\qquad \\textbf{(D)}\\ 52 \\qquad \\textbf{(E)}\\ 68$", "description_html": "<p>The number obtained from the last two nonzero digits of  <span class=\"katex--inline\">90!</span>  is equal to  <span class=\"katex--inline\">n</span> . What is  <span class=\"katex--inline\">n</span> ?</p>\n<p> <span class=\"katex--inline\">\\textbf{(A)}\\ 12 \\qquad \\textbf{(B)}\\ 32 \\qquad \\textbf{(C)}\\ 48 \\qquad \\textbf{(D)}\\ 52 \\qquad \\textbf{(E)}\\ 68</span> </p>\n<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 4, "problem_name": "2010 AMC 10A Problem 24", "can_next": true, "can_prev": true, "nxt": "/problem/10_amc10A_p25", "prev": "/problem/10_amc10A_p23"}}