{"status": "success", "data": {"description_md": "Let $f_1(x) = \\frac{2}{3}-\\frac{3}{3x+1}$, and for $n \\ge 2$, define $f_n(x) = f_1(f_{n-1} (x))$. The value of x that satisfies $f_{1001}(x) = x - 3$ can be expressed in the form $\\frac{m}{n}$,<br>where $m$ and $n$ are relatively prime positive integers. Find $m + n$.\n___\nLeading zeroes must be inputted, so if your answer is `34`, then input `034`. Full credit goes to [MAA](https://maa.org/) for authoring these problems. These problems were taken on the [AOPS](https://artofproblemsolving.com/) website.", "description_html": "<p>Let <span class=\"katex--inline\">f_1(x) = \\frac{2}{3}-\\frac{3}{3x+1}</span>, and for <span class=\"katex--inline\">n \\ge 2</span>, define <span class=\"katex--inline\">f_n(x) = f_1(f_{n-1} (x))</span>. The value of x that satisfies <span class=\"katex--inline\">f_{1001}(x) = x - 3</span> can be expressed in the form <span class=\"katex--inline\">\\frac{m}{n}</span>,<br/>where <span class=\"katex--inline\">m</span> and <span class=\"katex--inline\">n</span> are relatively prime positive integers. Find <span class=\"katex--inline\">m + n</span>.</p>&#10;<hr><p>Leading zeroes must be inputted, so if your answer is <code>34</code>, then input <code>034</code>. Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 5, "problem_name": "2012 AIME II Problem 11", "can_next": true, "can_prev": true, "nxt": "/problem/12_aime_II_p12", "prev": "/problem/12_aime_II_p10"}}