{"status": "success", "data": {"description_md": "The number $2013$ is expressed in the form $$2013 = \\frac {a_1!a_2!...a_m!}{b_1!b_2!...b_n!},$$<br />where $a_1 \\ge a_2 \\ge ... \\ge a_m$ and $b_1 \\ge b_2 \\ge ... \\ge b_n$ are positive integers and $a_1 + b_1$ is as small as possible. What is $|a_1 - b_1|$?\n\n$\\textbf{(A)}\\ 1 \\qquad \\textbf{(B)}\\ 2 \\qquad \\textbf{(C)}\\ 3 \\qquad \\textbf{(D)}\\ 4 \\qquad \\textbf{(E)}\\ 5$\n___\nFull credit goes to [MAA](https://maa.org/) for authoring these problems. These problems were taken on the [AOPS](https://artofproblemsolving.com/) website.", "description_html": "<p>The number <span class=\"katex--inline\">2013</span> is expressed in the form <span class=\"katex--display\">2013 = \\frac {a_1!a_2!...a_m!}{b_1!b_2!...b_n!},</span><br/>where <span class=\"katex--inline\">a_1 \\ge a_2 \\ge ... \\ge a_m</span> and <span class=\"katex--inline\">b_1 \\ge b_2 \\ge ... \\ge b_n</span> are positive integers and <span class=\"katex--inline\">a_1 + b_1</span> is as small as possible. What is <span class=\"katex--inline\">|a_1 - b_1|</span>?</p>&#10;<p><span class=\"katex--inline\">\\textbf{(A)}\\ 1 \\qquad \\textbf{(B)}\\ 2 \\qquad \\textbf{(C)}\\ 3 \\qquad \\textbf{(D)}\\ 4 \\qquad \\textbf{(E)}\\ 5</span></p>&#10;<hr/>&#10;<p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>&#10;", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 3, "problem_name": "2013 AMC 12B Problem 15", "can_next": true, "can_prev": true, "nxt": "/problem/13_amc12B_p16", "prev": "/problem/13_amc12B_p14"}}