{"status": "success", "data": {"description_md": "There is a real $n$ such that $(n+1)! + (n+2)! = n! \\cdot 440$. What is the sum of the digits of $n$?\n\n$\\textbf{(A) }3\\qquad\\textbf{(B) }8\\qquad\\textbf{(C) }10\\qquad\\textbf{(D) }11\\qquad\\textbf{(E) }12$", "description_html": "<p>There is a real  <span class=\"katex--inline\">n</span>  such that  <span class=\"katex--inline\">(n+1)! + (n+2)! = n! \\cdot 440</span> . What is the sum of the digits of  <span class=\"katex--inline\">n</span> ?</p>\n<p> <span class=\"katex--inline\">\\textbf{(A) }3\\qquad\\textbf{(B) }8\\qquad\\textbf{(C) }10\\qquad\\textbf{(D) }11\\qquad\\textbf{(E) }12</span> </p>\n<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 1, "problem_name": "2019 AMC 10B Problem 6", "can_next": true, "can_prev": true, "nxt": "/problem/19_amc10B_p07", "prev": "/problem/19_amc10B_p05"}}