{"status": "success", "data": {"description_md": "The quiz scores of a class with $k > 12$ students have a mean of $8$. The mean of a collection of $12$ of these quiz scores is $14$. What is the mean of the remaining quiz scores in terms of $k$?\n\n$\\textbf{(A)} ~\\frac{14-8}{k-12} \\qquad\\textbf{(B)} ~\\frac{8k-168}{k-12} \\qquad\\textbf{(C)} ~\\frac{14}{12} - \\frac{8}{k} \\qquad\\textbf{(D)} ~\\frac{14(k-12)}{k^2} \\qquad\\textbf{(E)} ~\\frac{14(k-12)}{8k}$", "description_html": "<p>The quiz scores of a class with  <span class=\"katex--inline\">k &gt; 12</span>  students have a mean of  <span class=\"katex--inline\">8</span> . The mean of a collection of  <span class=\"katex--inline\">12</span>  of these quiz scores is  <span class=\"katex--inline\">14</span> . What is the mean of the remaining quiz scores in terms of  <span class=\"katex--inline\">k</span> ?</p>\n<p> <span class=\"katex--inline\">\\textbf{(A)} ~\\frac{14-8}{k-12} \\qquad\\textbf{(B)} ~\\frac{8k-168}{k-12} \\qquad\\textbf{(C)} ~\\frac{14}{12} - \\frac{8}{k} \\qquad\\textbf{(D)} ~\\frac{14(k-12)}{k^2} \\qquad\\textbf{(E)} ~\\frac{14(k-12)}{8k}</span> </p>\n<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 1, "problem_name": "2021 AMC 10A Problem 5", "can_next": true, "can_prev": true, "nxt": "/problem/21_amc10A_p06", "prev": "/problem/21_amc10A_p04"}}