{"status": "success", "data": {"description_md": "Let $ABCD$ be a parallelogram with area $15$. Points $P$ and $Q$ are the projections of $A$ and $C,$ respectively, onto the line $BD;$ and points $R$ and $S$ are the projections of $B$ and $D,$ respectively, onto the line $AC.$ See the figure, which also shows the relative locations of these points.<br><center><img class=\"problem-image\" alt='[asy] size(350); defaultpen(linewidth(0.8)+fontsize(11)); real theta = aTan(1.25/2); pair A = 2.5*dir(180+theta), B = (3.35,0), C = -A, D = -B, P = foot(A,B,D), Q = -P, R = foot(B,A,C), S = -R; draw(A--B--C--D--A^^B--D^^R--S^^rightanglemark(A,P,D,6)^^rightanglemark(C,Q,D,6)); draw(B--R^^C--Q^^A--P^^D--S,linetype(\"4 4\")); dot(\"$A$\",A,dir(270)); dot(\"$B$\",B,E); dot(\"$C$\",C,N); dot(\"$D$\",D,W); dot(\"$P$\",P,SE); dot(\"$Q$\",Q,NE); dot(\"$R$\",R,N); dot(\"$S$\",S,dir(270)); [/asy]' class=\"latexcenter\" height=\"285\" src=\"https://latex.artofproblemsolving.com/d/3/5/d357d6211c4c672e68a32c940ef9ef86b8947dd2.png\" width=\"585\"/></center><br>Suppose $PQ=6$ and $RS=8,$ and let $d$ denote the length of $\\overline{BD},$ the longer diagonal of $ABCD.$ Then $d^2$ can be written in the form $m+n\\sqrt p,$ where $m,n,$ and $p$ are positive integers and $p$ is not divisible by the square of any prime. What is $m+n+p?$\n\n$\\textbf{(A) }81 \\qquad \\textbf{(B) }89 \\qquad \\textbf{(C) }97\\qquad \\textbf{(D) }105 \\qquad \\textbf{(E) }113$\n___\nFull credit goes to [MAA](https://maa.org/) for authoring these problems. These problems were taken on the [AOPS](https://artofproblemsolving.com/) website.", "description_html": "<p>Let  <span class=\"katex--inline\">ABCD</span>  be a parallelogram with area  <span class=\"katex--inline\">15</span> . Points  <span class=\"katex--inline\">P</span>  and  <span class=\"katex--inline\">Q</span>  are the projections of  <span class=\"katex--inline\">A</span>  and  <span class=\"katex--inline\">C,</span>  respectively, onto the line  <span class=\"katex--inline\">BD;</span>  and points  <span class=\"katex--inline\">R</span>  and  <span class=\"katex--inline\">S</span>  are the projections of  <span class=\"katex--inline\">B</span>  and  <span class=\"katex--inline\">D,</span>  respectively, onto the line  <span class=\"katex--inline\">AC.</span>  See the figure, which also shows the relative locations of these points.<br/><center><img class=\"latexcenter\" alt=\"[asy] size(350); defaultpen(linewidth(0.8)+fontsize(11)); real theta = aTan(1.25/2); pair A = 2.5*dir(180+theta), B = (3.35,0), C = -A, D = -B, P = foot(A,B,D), Q = -P, R = foot(B,A,C), S = -R; draw(A--B--C--D--A^^B--D^^R--S^^rightanglemark(A,P,D,6)^^rightanglemark(C,Q,D,6)); draw(B--R^^C--Q^^A--P^^D--S,linetype(&#34;4 4&#34;)); dot(&#34;$A$&#34;,A,dir(270)); dot(&#34;$B$&#34;,B,E); dot(&#34;$C$&#34;,C,N); dot(&#34;$D$&#34;,D,W); dot(&#34;$P$&#34;,P,SE); dot(&#34;$Q$&#34;,Q,NE); dot(&#34;$R$&#34;,R,N); dot(&#34;$S$&#34;,S,dir(270)); [/asy]\" height=\"285\" src=\"https://latex.artofproblemsolving.com/d/3/5/d357d6211c4c672e68a32c940ef9ef86b8947dd2.png\" width=\"585\"/></center><br/>Suppose  <span class=\"katex--inline\">PQ=6</span>  and  <span class=\"katex--inline\">RS=8,</span>  and let  <span class=\"katex--inline\">d</span>  denote the length of  <span class=\"katex--inline\">\\overline{BD},</span>  the longer diagonal of  <span class=\"katex--inline\">ABCD.</span>  Then  <span class=\"katex--inline\">d^2</span>  can be written in the form  <span class=\"katex--inline\">m+n\\sqrt p,</span>  where  <span class=\"katex--inline\">m,n,</span>  and  <span class=\"katex--inline\">p</span>  are positive integers and  <span class=\"katex--inline\">p</span>  is not divisible by the square of any prime. What is  <span class=\"katex--inline\">m+n+p?</span> </p>&#10;<p> <span class=\"katex--inline\">\\textbf{(A) }81 \\qquad \\textbf{(B) }89 \\qquad \\textbf{(C) }97\\qquad \\textbf{(D) }105 \\qquad \\textbf{(E) }113</span> </p>&#10;<hr><p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 5, "problem_name": "2021 AMC 12B Problem 24", "can_next": true, "can_prev": true, "nxt": "/problem/21_amc12B_p25", "prev": "/problem/21_amc12B_p23"}}