{"status": "success", "data": {"description_md": "$P$ is a point interior to rectangle $ABCD$ and such that $PA = 3$ inches, $PD = 4$ inches, and $PC = 5$ inches. Then $PB$, in inches, equals:\n\n<center><img class=\"problem-image\" src=\"/static/AHSME/1964/crops/64_ahsme_p33_fig.png\" alt=\"figure\" width=\"274\"></center>\n\n$\\text{(A)}\\ 2\\sqrt{3}\\qquad\\text{(B)}\\ 3\\sqrt{2}\\qquad\\text{(C)}\\ 3\\sqrt{3}\\qquad\\text{(D)}\\ 4\\sqrt{2}\\qquad\\text{(E)}\\ 2$\n\n___\n\nFull credit goes to [MAA](https://maa.org/) for authoring these problems. These problems were taken on the [AOPS](https://artofproblemsolving.com/) website.\n", "description_html": "<p><span class=\"katex--inline\">P</span> is a point interior to rectangle <span class=\"katex--inline\">ABCD</span> and such that <span class=\"katex--inline\">PA = 3</span> inches, <span class=\"katex--inline\">PD = 4</span> inches, and <span class=\"katex--inline\">PC = 5</span> inches. Then <span class=\"katex--inline\">PB</span>, in inches, equals:</p>\n<center><img class=\"problem-image\" src=\"/static/AHSME/1964/crops/64_ahsme_p33_fig.png\" alt=\"figure\" width=\"274\"></center>\n<p><span class=\"katex--inline\">\\text{(A)}\\ 2\\sqrt{3}\\qquad\\text{(B)}\\ 3\\sqrt{2}\\qquad\\text{(C)}\\ 3\\sqrt{3}\\qquad\\text{(D)}\\ 4\\sqrt{2}\\qquad\\text{(E)}\\ 2</span></p>\n<hr>\n<p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>\n", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 3, "problem_name": "1964 AHSME Problem 33", "can_next": true, "can_prev": true, "nxt": "/problem/64_ahsme_p34", "prev": "/problem/64_ahsme_p32"}}