{"status": "success", "data": {"description_md": "If $x, y$, and $y - \\dfrac{1}{x}$ are not $0$, then\n$$\\frac{x - \\frac{1}{y}}{y - \\frac{1}{x}}$$\nequals\n\n$\\text{(A)}\\ 1\\qquad\\text{(B)}\\ \\frac{x}{y}\\qquad\\text{(C)}\\ \\frac{y}{x}\\qquad\\text{(D)}\\ \\frac{x}{y} - \\frac{y}{x}\\qquad\\text{(E)}\\ xy - \\frac{1}{xy}$\n\n___\n\nFull credit goes to [MAA](https://maa.org/) for authoring these problems. These problems were taken on the [AOPS](https://artofproblemsolving.com/) website.\n", "description_html": "<p>If <span class=\"katex--inline\">x, y</span>, and <span class=\"katex--inline\">y - \\dfrac{1}{x}</span> are not <span class=\"katex--inline\">0</span>, then\n<span class=\"katex--display\">\\frac{x - \\frac{1}{y}}{y - \\frac{1}{x}}</span>\nequals</p>\n<p><span class=\"katex--inline\">\\text{(A)}\\ 1\\qquad\\text{(B)}\\ \\frac{x}{y}\\qquad\\text{(C)}\\ \\frac{y}{x}\\qquad\\text{(D)}\\ \\frac{x}{y} - \\frac{y}{x}\\qquad\\text{(E)}\\ xy - \\frac{1}{xy}</span></p>\n<hr>\n<p>Full credit goes to <a href=\"https://maa.org/\">MAA</a> for authoring these problems. These problems were taken on the <a href=\"https://artofproblemsolving.com/\">AOPS</a> website.</p>\n", "hints_md": "", "hints_html": "", "editorial_md": "", "editorial_html": "", "flag_hint": "", "point_value": 1, "problem_name": "1984 AHSME Problem 2", "can_next": true, "can_prev": true, "nxt": "/problem/84_ahsme_p03", "prev": "/problem/84_ahsme_p01"}}