Problem
2000 AIME I Problem 10
A sequence of numbers x_{1},x_{2},x_{3},\ldots,x_{100} has the property that, for every integer k between 1 and 100, inclusive, the number x_{k} is k less than the sum of the other 99 numbers. Given that x_{50} = \frac{m}{n}, where m and n are relatively prime positive integers, find m + n.
Leading zeroes must be inputted, so if your answer is 34, then input 034
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