Problem
2000 AIME I Problem 14
In triangle ABC, it is given that angles B and C are congruent. Points P and Q lie on \overline{AC} and \overline{AB}, respectively, so that AP = PQ = QB = BC. Angle ACB is r times as large as angle APQ, where r is a positive real number. Find \lfloor 1000r \rfloor.
Leading zeroes must be inputted, so if your answer is 34, then input 034
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