2000 Fermat Problem 14

In the regular hexagon ABCDEF, two of the diagonals, FC and BD, intersect at G. The ratio of the area of quadrilateral FEDG to the area of \triangle BCG is

\textbf{(A)}\ 3\sqrt{3}:1\quad \textbf{(B)}\ 4:1\quad \textbf{(C)}\ 6:1\quad \textbf{(D)}\ 2\sqrt{3}:1\quad \textbf{(E)}\ 5:1

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