Problem

2001 AMC 12 Problem 24

In \triangle ABC, \angle ABC=45^\circ. Point D is on \overline{BC} so that 2\cdot BD=CD and \angle DAB=15^\circ. Find \angle ACB.

\text{(A) }54^\circ \qquad \text{(B) }60^\circ \qquad \text{(C) }72^\circ \qquad \text{(D) }75^\circ \qquad \text{(E) }90^\circ


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