2001 Fermat Problem 20

Point P is on the line y=5x+3. The coordinates of point Q are (3,-2). If M is the midpoint of PQ, then M must lie on the line

\textbf{(A)}\ y=\frac{5}{2}x-\frac{7}{2}\quad \textbf{(B)}\ y=5x+1\quad \textbf{(C)}\ y=-\frac{1}{5}x-\frac{7}{5}\quad \textbf{(D)}\ y=\frac{5}{2}x+\frac{1}{2}\quad \textbf{(E)}\ y=5x-7

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