Problem

2002 AMC 10A Problem 25

[asy] pair A,B,C,D; A=(0,0); B=(52,0); C=(38,20); D=(5,20); dot(A); dot(B); dot(C); dot(D); draw(A--B--C--D--cycle); label("$A$",A,S); label("$B$",B,S); label("$C$",C,N); label("$D$",D,N); label("52",(A+B)/2,S); label("39",(C+D)/2,N); label("12",(B+C)/2,E); label("5",(D+A)/2,W); [/asy]

In trapezoid

ABCD

with bases

AB

and

CD

, we have

AB = 52

BC = 12

CD = 39

, and

DA = 5

. The area of

ABCD

$\text{(A)}\ 182 \qquad \text{(B)}\ 195 \qquad \text{(C)}\ 210 \qquad \text{(D)}\ 234 \qquad \text{(E)}\ 260$

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.

Show/Hide Problem Tags

Problem Tags: Geometry

Want to contribute problems and receive full credit? Click here to add your problem!
Please report any issues to us in our Discord server
Go to previous contest problem (SHIFT + Left Arrow)

Problem feedback

Difficulty —

Category: AMC 10A
Points: 4
Back to practice
Train more like this