2002 Pascal Problem 12

In a sequence of numbers, each number, except the first, equals twice the previous number. If the sum of the second and third numbers in the list is 24, then the *sixth* number is

\textbf{(A)}\ 112\quad \textbf{(B)}\ 192\quad \textbf{(C)}\ 64\quad \textbf{(D)}\ 40\quad \textbf{(E)}\ 128

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Pascal contests here.