2003 Fermat Problem 4

In the diagram, the numbers 1 to 10 are placed around a circle. Sandy crosses out 1, then 4, and then 7. Continuing in a clockwise direction, she crosses out every third number of those remaining, until only two numbers are left. The sum of these two numbers is

\textbf{(A)}\ 13\quad \textbf{(B)}\ 10\quad \textbf{(C)}\ 8\quad \textbf{(D)}\ 14\quad \textbf{(E)}\ 17

If there are no answer choices shown, enter a numerical answer.

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