Problem
2005 AMC 10B Problem 11
The first term of a sequence is 2005. Each succeeding term is the sum of the cubes of the digits of the previous term. What is the {2005}^{\text{th}} term of the sequence?
\mathrm{(A)} 29 \qquad \mathrm{(B)} 55 \qquad \mathrm{(C)} 85 \qquad \mathrm{(D)} 133 \qquad \mathrm{(E)} 250
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