Problem
2006 AIME II Problem 6
Square ABCD has sides of length 1. Points E and F are on \overline{BC} and \overline{CD}, respectively, so that \triangle AEF is equilateral. A square with vertex B has sides that are parallel to those of ABCD and a vertex on \overline{AE}. The length of a side of this smaller square is \frac{a-\sqrt{b}}{c}, where a, b, and c are positive integers and b is not divisible by the square of any prime. Find a+b+c.
Leading zeroes must be inputted, so if your answer is 34, then input 034
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