Problem
2007 AIME I Problem 11
For each positive integer p, let b(p) denote the unique positive integer k such that |k-\sqrt{p}| < \frac{1}{2}. For example, b(6) = 2 and b(23) = 5. If S = \sum_{p=1}^{2007} b(p), find the remainder when S is divided by 1000.
Leading zeroes must be inputted, so if your answer is 34, then input 034
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