2007 Fermat Problem 7

The product of three positive integers is 42. The sum of two of these integers is 9. The third integer is

\textbf{(A)}\ 1\quad \textbf{(B)}\ 7\quad \textbf{(C)}\ 6\quad \textbf{(D)}\ 3\quad \textbf{(E)}\ 2

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Fermat contests here.