2008 Fermat Problem 21

Suppose N = 1 + 11 + 101 + 1001 + 10001 + \ldots + 1\overbrace{000\ldots0000}1. When N is calculated and written as a single integer, the sum of its digits is

\textbf{(A)}\ 58\quad \textbf{(B)}\ 99\quad \textbf{(C)}\ 55\quad \textbf{(D)}\ 50\quad \textbf{(E)}\ 103

If there are no answer choices shown, enter a numerical answer.

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