Problem
2009 AMC 10B Problem 20
Triangle ABC has a right angle at B, AB=1, and BC=2. The angle bisector of \angle A intersects side \overline{BC} at D. What is BD?
\text{(A) } \frac {\sqrt3 - 1}{2} \qquad \text{(B) } \frac {\sqrt5 - 1}{2} \qquad \text{(C) } \frac {\sqrt5 + 1}{2} \qquad \text{(D) } \frac {\sqrt6 + \sqrt2}{2} \qquad \text{(E) } 2\sqrt 3 - 1
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