2011 Fermat Problem 6

When three consecutive integers are added, the total is 27. When the same three integers are multiplied, the result is

\textbf{(A)}\ 504\quad \textbf{(B)}\ 81\quad \textbf{(C)}\ 720\quad \textbf{(D)}\ 729\quad \textbf{(E)}\ 990

If there are no answer choices shown, enter a numerical answer.

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