Problem

2012 AMC 12A Problem 10

A triangle has area 30, one side of length 10, and the median to that side of length 9. Let \theta be the acute angle formed by that side and the median. What is \sin{\theta}?

\textbf{(A)}\ \frac{3}{10}\qquad\textbf{(B)}\ \frac{1}{3}\qquad\textbf{(C)}\ \frac{9}{20}\qquad\textbf{(D)}\ \frac{2}{3}\qquad\textbf{(E)}\ \frac{9}{10}


Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.


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Problem Tags: 2-d Geometry Trigonometry

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