2012 Pascal Problem 24

The smallest of nine consecutive integers is 2012. These nine integers are placed in the circles to the right. The sum of the three integers along each of the four lines is the same. If this sum is as small as possible, what is the value of u?

\textbf{(A)}\ 2012\quad \textbf{(B)}\ 2013\quad \textbf{(C)}\ 2014\quad \textbf{(D)}\ 2015\quad \textbf{(E)}\ 2016

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Pascal contests here.