2016 AMC 10A Problem 19


In rectangle ABCD,ABCD, AB=6AB=6 and BC=3BC=3. Point EE between BB and CC, and point FF between EE and CC are such that BE=EF=FCBE=EF=FC. Segments AE\overline{AE} and AF\overline{AF} intersect BD\overline{BD} at PP and QQ, respectively. The ratio BP:PQ:QDBP:PQ:QD can be written as r:s:tr:s:t where the greatest common factor of r,sr,s and tt is 11. What is r+s+tr+s+t?

(A) 7(B) 9(C) 12(D) 15(E) 20\textbf{(A) } 7 \qquad \textbf{(B) } 9 \qquad \textbf{(C) } 12 \qquad \textbf{(D) } 15 \qquad \textbf{(E) } 20

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Category: AMC 10A
Points: 3
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