2017 Fermat Problem 12

Digits are placed in the two boxes of 2\square\square, with one digit in each box, to create a three-digit positive integer. In how many ways can this be done so that the three-digit positive integer is larger than 217?

\textbf{(A)}\ 81\quad \textbf{(B)}\ 82\quad \textbf{(C)}\ 83\quad \textbf{(D)}\ 92\quad \textbf{(E)}\ 93

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Fermat contests here.