2018 AMC 10A Problem 4


How many ways can a student schedule 33 mathematics courses — algebra, geometry, and number theory — in a 66-period day if no two mathematics courses can be taken in consecutive periods? (What courses the student takes during the other 33 periods is of no concern here.)

(A) 3(B) 6(C) 12(D) 18(E) 24\textbf{(A) }3\qquad\textbf{(B) }6\qquad\textbf{(C) }12\qquad\textbf{(D) }18\qquad\textbf{(E) }24

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Problem Tags: Counting and probability

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Category: AMC 10A
Points: 1
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