Problem
2023 AIME I Problem 10
There exists a unique positive integer a for which the sum \[U = \sum_{n=1}^{2023} \left\lfloor \frac{n^2 - na}{5} \right\rfloor\] is an integer strictly between -1000 and 1000. For that unique a, find a + U.
(Note that \lfloor x \rfloor denotes the greatest integer that is less than or equal to x.)
Leading zeroes must be inputted, so if your answer is 34, then input 034
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