2026 Fermat Problem 19

There are 28 balls in a bag. Each ball is coloured 1 of 7 colours and has 1 of 4 patterns. No two balls have the same colour and pattern combination. Exactly 3 balls are removed from the bag, one at a time without replacement. What is the probability that one of the last two balls removed matches the colour of the first ball and the other matches the pattern of the first ball?

\textbf{(A)}\ \dfrac{1}{14}\quad \textbf{(B)}\ \dfrac{2}{39}\quad \textbf{(C)}\ \dfrac{28}{351}\quad \textbf{(D)}\ \dfrac{1}{13}\quad \textbf{(E)}\ \dfrac{4}{39}

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