1950 AHSME Problem 1

If 64 is divided into three parts proportional to 2, 4, and 6, the smallest part is:

\textbf{(A)}\ 5\frac{1}{3}\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 10\frac{2}{3}\qquad\textbf{(D)}\ 5\qquad\textbf{(E)}\ \text{None of these answers}

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.