Problem
1951 AHSME Problem 18
The expression 21x^2+ax+21 is to be factored into prime binomial factors and without a numerical monomial factor. This can be done if the value ascribed to a is:
\textbf{(A)}\ \text{any odd number}\qquad\textbf{(B)}\ \text{some odd number}\qquad\textbf{(C)}\ \text{any even number}\qquad\textbf{(D)}\ \text{some even number}\qquad\textbf{(E)}\ \text{zero}
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