1952 AHSME Problem 36

To be continuous at x = - 1, the value of \frac {x^3 + 1}{x^2 - 1} is taken to be:

\textbf{(A)}\ - 2 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ \frac {3}{2} \qquad \textbf{(D)}\ \infty \qquad \textbf{(E)}\ -\frac{3}{2}

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.