1957 AHSME Problem 7

The area of a circle inscribed in an equilateral triangle is 48\pi. The perimeter of this triangle is:

\textbf{(A)}\ 72\sqrt{3} \qquad \textbf{(B)}\ 48\sqrt{3}\qquad \textbf{(C)}\ 36\qquad \textbf{(D)}\ 24\qquad \textbf{(E)}\ 72

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.