1958 AHSME Problem 34

The numerator of a fraction is 6x + 1, then denominator is 7 - 4x, and x can have any value between -2 and 2, both included. The values of x for which the numerator is greater than the denominator are:

\begin{array}{l} \textbf{(A)}\ \frac{3}{5} < x \le 2\qquad \textbf{(B)}\ \frac{3}{5} \le x \le 2\qquad \textbf{(C)}\ 0 < x \le 2\qquad \\ \textbf{(D)}\ 0 \le x \le 2\qquad \textbf{(E)}\ -2 \le x \le 2 \end{array}

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.