1961 AHSME Problem 24

Thirty-one books are arranged from left to right in order of increasing prices. The price of each book differs by \${2} from that of each adjacent book. For the price of the book at the extreme right a customer can buy the middle book and the adjacent one. Then:

\begin{array}{l} \textbf{(A)}\ \text{The adjacent book referred to is at the left of the middle book}\qquad \\ \textbf{(B)}\ \text{The middle book sells for \$36} \qquad \\ \textbf{(C)}\ \text{The cheapest book sells for \$4} \qquad \\ \textbf{(D)}\ \text{The most expensive book sells for \$64 } \qquad \\ \textbf{(E)}\ \text{None of these is correct } \end{array}

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.