Problem
1974 AHSME Problem 19
In the adjoining figure ABCD is a square and CMN is an equilateral triangle. If the area of ABCD is one square inch, then the area of CMN in square inches is
\mathrm{(A)\ } 2\sqrt{3}-3 \qquad \mathrm{(B) \ }1-\frac{\sqrt{3}}{3} \qquad \mathrm{(C) \ } \frac{\sqrt{3}}{4} \qquad \mathrm{(D) \ } \frac{\sqrt{2}}{3} \qquad \mathrm{(E) \ }4-2\sqrt{3}
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