Problem
1975 AHSME Problem 23
In the adjoining figure AB and BC are adjacent sides of square ABCD; M is the midpoint of AB; N is the midpoint of BC; and AN and CM intersect at O. The ratio of the area of AOCD to the area of ABCD is
\textbf{(A)}\ \frac{5}{6}\qquad \textbf{(B)}\ \frac{3}{4}\qquad \textbf{(C)}\ \frac{2}{3}\qquad \textbf{(D)}\ \frac{\sqrt{3}}{2}\qquad \textbf{(E)}\ \frac{(\sqrt{3}-1)}{2}
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