1997 Fermat Problem 22

If 2x^2 - 2xy + y^2 = 289, where x and y are integers and x \ge 0, the number of different ordered pairs (x, y) which satisfy this equation is

\textbf{(A)}\ 8\quad \textbf{(B)}\ 7\quad \textbf{(C)}\ 5\quad \textbf{(D)}\ 4\quad \textbf{(E)}\ 3

If there are no answer choices shown, enter a numerical answer.

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