2007 Cayley Problem 13

In the diagram, \triangle ABC is right-angled at C. Also, points M, N and P are the midpoints of sides BC, AC and AB, respectively. If the area of \triangle APN is 2 cm^2, then the area of \triangle ABC is

\textbf{(A)}\ 8\text{ cm}^2\quad \textbf{(B)}\ 16\text{ cm}^2\quad \textbf{(C)}\ 6\text{ cm}^2\quad \textbf{(D)}\ 4\text{ cm}^2\quad \textbf{(E)}\ 12\text{ cm}^2

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Cayley contests here.