2009 Cayley Problem 12

In the table shown, a sequence starts with 2 in the top left corner. Moving across each row, each box is filled with a number 3 greater than the number to its left. The leftmost number in each row is 3 greater than the greatest in the previous row. When all of the boxes are filled in, the value of x is

\begin{array}{|c|c|c|c|c|c|}\hline 2 & 5 & 8 & 11 & 14 & 17 \\ \hline 20 & 23 & 26 & 29 & 32 & 35 \\ \hline 38 & & & & & \\ \hline & & & & & \\ \hline & & & & & \\ \hline & & & & & x \\ \hline \end{array}

\textbf{(A)}\ 101\quad \textbf{(B)}\ 104\quad \textbf{(C)}\ 107\quad \textbf{(D)}\ 110\quad \textbf{(E)}\ 113

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Cayley contests here.