2011 Cayley Problem 8

If 2.4 \times 10^8 is doubled, then the result is equal to

\textbf{(A)}\ 2.4 \times 20^8\quad \textbf{(B)}\ 4.8 \times 20^8\quad \textbf{(C)}\ 4.8 \times 10^8\quad \textbf{(D)}\ 2.4 \times 10^{16}\quad \textbf{(E)}\ 4.8 \times 10^{16}

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Cayley contests here.