2011 Cayley Problem 18

When 100 is divided by 12, the remainder is 4. When 100 is divided by a positive integer x, the remainder is 10. When 1000 is divided by x, the remainder is

\textbf{(A)}\ 10\quad \textbf{(B)}\ 100\quad \textbf{(C)}\ 0\quad \textbf{(D)}\ 1\quad \textbf{(E)}\ 90

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Cayley contests here.