2013 Fermat Problem 12

An integer m is chosen at random from the list -9,-7,-5,-3,-1,1,3,5,7,9. The probability that m^4 > 100 is

\textbf{(A)}\ \frac{1}{5}\quad \textbf{(B)}\ \frac{3}{10}\quad \textbf{(C)}\ \frac{1}{2}\quad \textbf{(D)}\ \frac{2}{5}\quad \textbf{(E)}\ \frac{3}{5}

If there are no answer choices shown, enter a numerical answer.

Full credit to this problem is given to the CEMC, you may view all Fermat contests here.