2013 Fermat Problem 22

Megan and Shana race against each other with the winner of each race receiving x gold coins and the loser receiving y gold coins. (There are no ties and x and y are integers with x > y > 0.) After several races, Megan has 42 coins and Shana has 35 coins. Shana has won exactly 2 races. The value of x is

\textbf{(A)}\ 3\quad \textbf{(B)}\ 7\quad \textbf{(C)}\ 5\quad \textbf{(D)}\ 6\quad \textbf{(E)}\ 4

If there are no answer choices shown, enter a numerical answer.

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