1953 AHSME Problem 23

The equation \sqrt {x + 10} - \frac {6}{\sqrt {x + 10}} = 5 has:

\begin{array}{l} \textbf{(A)}\ \text{an extraneous root between } - 5\text{ and } - 1 \\ \textbf{(B)}\ \text{an extraneous root between }-10\text{ and }-6\\ \textbf{(C)}\ \text{a true root between }20\text{ and }25\qquad \textbf{(D)}\ \text{two true roots}\\ \textbf{(E)}\ \text{two extraneous roots} \end{array}

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.