1958 AHSME Problem 39

We may say concerning the solution of |x|^2 + |x| - 6 =0 that:

\begin{array}{l} \textbf{(A)}\ \text{there is only one root}\qquad \textbf{(B)}\ \text{the sum of the roots is }{+1}\qquad \textbf{(C)}\ \text{the sum of the roots is }{0}\qquad \\ \textbf{(D)}\ \text{the product of the roots is }{+4}\qquad \textbf{(E)}\ \text{the product of the roots is }{-6} \end{array}

Full credit goes to MAA for authoring these problems. These problems were taken on the AOPS website.